Java to PHP

[canardo]

private static String decrypt2(long message,int key1,int key2){
        StringBuffer output=new StringBuffer();
        
	message=message^key1;
        int length=(byte)(message);        
        byte input[]=new byte[length];
        for (int i=length-1;i>=0;i--){            
            message=message>>8;
            input[i]=(byte)(message^key2);
        }             
        for (int i=0;i<length;i++){            
            output.append((char)input[i]);
           //System.out.println("\toutput: "+(byte)input[i]);
        }
        return output.toString();
    }

Could really do with the above code being converted into php, one question thats stopping me doing it myself is how can I get the byte blocks in a language that only gives me $var

Thanks for any help

[canardo]

<?php

function decrypt($message)
{
	$key1 = 23555;
	$key2 = 77;

	$output = "";

	$length = $message & 0xFF;
	echo $length;
	for($i = $length-1; $i>=0; $i--)
	{
		$message >>= 8;
		$output = ($message ^ $key2).$output;
	}
	return $output;
}

$m = 9186913876452331524;
$var = decrypt($m);
echo "<br /> decrypt".$m.") <br /> = ". $var ;

?>

length unfortunately is 0 which bit is it that php doesnt like the & or the 0xff

[Fusen]

try

$length = $message . 0xFF;

you'll then get output, if it's actually the output you want is a different matter ;P

[canardo]

haha not quite unforunately cheers though fusen

for anyone thats interested got it done in the end

<?php

function decrypt($message)
{
	$key1 = 23555;
	$key2 = 77;

	$output = "";

	echo "original message as hex = ".dechex($message)."<br><br>";

	$message ^= $key1;
	$length = $message & 255;

	echo "xor'd message as hex = ".dechex($message)."<br><br>";

	echo "length=".$length."<br>";
	for($i = 0; $i<$length; $i++){
		$message >>= 8;
		$input = ($message ^ $key2) & 255;
		echo "message = ".dechex($message)."<br>";
		echo "input = ".$input."<br>";
		$output = chr($input).$output;
	}
	return $output;
}

echo "decrypt(".$m.") = '".decrypt($m)."'";

?>